(x^2+x)(x^2+x-8)+12=0

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Solution for (x^2+x)(x^2+x-8)+12=0 equation: 


Simplifying
(x2 + x)(x2 + x + -8) + 12 = 0

Reorder the terms:
(x + x2)(x2 + x + -8) + 12 = 0

Reorder the terms:
(x + x2)(-8 + x + x2) + 12 = 0

Multiply (x + x2) * (-8 + x + x2)
(x(-8 + x + x2) + x2(-8 + x + x2)) + 12 = 0
((-8 * x + x * x + x2 * x) + x2(-8 + x + x2)) + 12 = 0
((-8x + x2 + x3) + x2(-8 + x + x2)) + 12 = 0
(-8x + x2 + x3 + (-8 * x2 + x * x2 + x2 * x2)) + 12 = 0
(-8x + x2 + x3 + (-8x2 + x3 + x4)) + 12 = 0

Reorder the terms:
(-8x + x2 + -8x2 + x3 + x3 + x4) + 12 = 0

Combine like terms: x2 + -8x2 = -7x2
(-8x + -7x2 + x3 + x3 + x4) + 12 = 0

Combine like terms: x3 + x3 = 2x3
(-8x + -7x2 + 2x3 + x4) + 12 = 0

Reorder the terms:
12 + -8x + -7x2 + 2x3 + x4 = 0

Solving
12 + -8x + -7x2 + 2x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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